Y=5x^2-12x+40

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Solution for Y=5x^2-12x+40 equation: 



=5Y^2-12Y+40

We move all terms to the left:

-(5Y^2-12Y+40)=0

We get rid of parentheses

-5Y^2+12Y-40=0

a = -5; b = 12; c = -40;
Δ = b2-4ac
Δ = 122-4·(-5)·(-40)
Δ = -656
Delta is less than zero, so there is no solution for the equation

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